Volume of a Single Lifesaver

Oct 13, 2025 by wbrum.org 140 views

Introduction

In this problem, we are tasked with finding the volume of a giant tube that holds 120 lifesavers. Each lifesaver has a diameter of 1.25 inches. To find the volume of the tube, we need to first find the volume of a single lifesaver and then multiply it by the number of lifesavers. We will use the formula for the volume of a cylinder, which is given by V = πr^2h, where r is the radius of the cylinder and h is its height.

Volume of a Single Lifesaver

To find the volume of a single lifesaver, we need to know its radius and height. The diameter of the lifesaver is given as 1.25 inches, so we can find the radius by dividing the diameter by 2. The radius of the lifesaver is therefore 1.25/2 = 0.625 inches.

The height of the lifesaver is not given, but we can assume it to be a cylinder with a height equal to its diameter. Therefore, the height of the lifesaver is also 1.25 inches.

Now, we can use the formula for the volume of a cylinder to find the volume of a single lifesaver:

V = πr^2h = π(0.625)^2(1.25) = 3.14(0.390625)(1.25) = 1.54 cubic inches

Volume of the Giant Tube

The volume of the giant tube is equal to the volume of a single lifesaver multiplied by the number of lifesavers. Therefore, the volume of the giant tube is:

V = 1.54 cubic inches/lifesaver x 120 lifesavers = 184.8 cubic inches

Rounding to the nearest place as instructed, the volume of the giant tube is approximately 185 cubic inches.

Conclusion

In this problem, we found the volume of a giant tube that holds 120 lifesavers. Each lifesaver has a diameter of 1.25 inches. We used the formula for the volume of a cylinder to find the volume of a single lifesaver and then multiplied it by the number of lifesavers to find the volume of the giant tube. The volume of the giant tube is approximately 185 cubic inches.

Mathematical Formulae Used

V = πr^2h (formula for the volume of a cylinder)

Variables Used

V: volume of the cylinder
π: mathematical constant approximately equal to 3.14
r: radius of the cylinder
h: height of the cylinder

Assumptions Made

The height of the lifesaver is equal to its diameter.

Limitations of the Problem

The problem assumes that the lifesavers are perfect cylinders with no irregularities.
The problem assumes that the giant tube is a perfect cylinder with no irregularities.

Future Improvements

To improve the accuracy of the problem, we could use a more precise value of π.
To improve the accuracy of the problem, we could use a more precise value of the diameter of the lifesaver.

References

None

Appendix

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Volume of a Single Lifesaver and the Giant Tube: Q&A =====================================================

Introduction

In our previous article, we discussed the problem of finding the volume of a giant tube that holds 120 lifesavers. Each lifesaver has a diameter of 1.25 inches. We used the formula for the volume of a cylinder to find the volume of a single lifesaver and then multiplied it by the number of lifesavers to find the volume of the giant tube. In this article, we will answer some frequently asked questions related to this problem.

Q: What is the formula for the volume of a cylinder?

A: The formula for the volume of a cylinder is V = πr^2h, where r is the radius of the cylinder and h is its height.

Q: What is the radius of the lifesaver?

A: The radius of the lifesaver is 0.625 inches, which is half of its diameter.

Q: What is the height of the lifesaver?

A: The height of the lifesaver is assumed to be equal to its diameter, which is 1.25 inches.

Q: How do we find the volume of the giant tube?

A: We find the volume of the giant tube by multiplying the volume of a single lifesaver by the number of lifesavers. Therefore, the volume of the giant tube is 1.54 cubic inches/lifesaver x 120 lifesavers = 184.8 cubic inches.

Q: Why do we use 3.14 as the value of π?

A: We use 3.14 as the value of π because it is a commonly used approximation of the mathematical constant π.

Q: What are the assumptions made in this problem?

A: The assumptions made in this problem are that the lifesavers are perfect cylinders with no irregularities and that the giant tube is a perfect cylinder with no irregularities.

Q: What are the limitations of this problem?

A: The limitations of this problem are that it assumes the lifesavers are perfect cylinders with no irregularities and that the giant tube is a perfect cylinder with no irregularities.

Q: How can we improve the accuracy of this problem?

A: We can improve the accuracy of this problem by using a more precise value of π and by using a more precise value of the diameter of the lifesaver.

Q: What are the mathematical formulae used in this problem?

A: The mathematical formula used in this problem is V = πr^2h, which is the formula for the volume of a cylinder.

Q: What are the variables used in this problem?

A: The variables used in this problem are V (volume of the cylinder), π (mathematical constant approximately equal to 3.14), r (radius of the cylinder), and h (height of the cylinder).