Understanding the Quadratic Inequality

Oct 13, 2025 by wbrum.org 20 views

Introduction

Quadratic inequalities are a type of mathematical expression that involves a quadratic function and an inequality sign. In this article, we will focus on solving the quadratic inequality $x(x-5) \leq 14$ . This type of inequality is commonly encountered in algebra and calculus, and it requires a thorough understanding of quadratic functions and their properties.

Understanding the Quadratic Inequality

The given quadratic inequality is $x(x-5) \leq 14$ . To solve this inequality, we need to first expand the left-hand side of the inequality to obtain a quadratic expression in the form of $ax^2 + bx + c$ . In this case, the quadratic expression is $x^2 - 5x$ .

Factoring the Quadratic Expression

To solve the quadratic inequality, we need to factor the quadratic expression $x^2 - 5x$ . Factoring a quadratic expression involves expressing it as a product of two binomial expressions. In this case, we can factor the quadratic expression as follows:

$x^2 - 5x = x(x - 5)$

This factorization allows us to rewrite the quadratic inequality as $x(x - 5) \leq 14$ .

Solving the Quadratic Inequality

To solve the quadratic inequality, we need to find the values of $x$ that satisfy the inequality. We can do this by using the following steps:

Find the critical points: The critical points of the quadratic inequality are the values of $x$ that make the quadratic expression equal to zero. In this case, the critical points are $x = 0$ and $x = 5$ .
Test the intervals: We need to test the intervals between the critical points to determine which intervals satisfy the inequality. The intervals are $(-\infty, 0)$ , $(0, 5)$ , and $(5, \infty)$ .
Determine the solution set: Based on the results of the interval testing, we can determine the solution set of the quadratic inequality.

Interval Testing

To test the intervals, we need to substitute a test value from each interval into the quadratic expression. If the result is less than or equal to 14, then the interval satisfies the inequality.

Interval $(-\infty, 0)$ : Let's choose $x = -1$ as a test value. Substituting $x = -1$ into the quadratic expression, we get $(-1)^2 - 5(-1) = 1 + 5 = 6$ . Since $6 \leq 14$ , the interval $(-\infty, 0)$ satisfies the inequality.
Interval $(0, 5)$ : Let's choose $x = 2$ as a test value. Substituting $x = 2$ into the quadratic expression, we get $2^2 - 5(2) = 4 - 10 = -6$ . Since $-6 \leq 14$ , the interval $(0, 5)$ satisfies the inequality.
Interval $(5, \infty)$ : Let's choose $x = 6$ as a test value. Substituting $x = 6$ into the quadratic expression, we get $6^2 - 5(6) = 36 - 30 = 6$ . Since $6 \leq 14$ , the interval $(5, \infty)$ satisfies the inequality.

Determining the Solution Set

Based on the results of the interval testing, we can determine the solution set of the quadratic inequality. The solution set is the union of the intervals that satisfy the inequality.

The solution set is $(-\infty, 0] \cup [2, 5] \cup [5, \infty)$ .

Conclusion

In this article, we solved the quadratic inequality $x(x-5) \leq 14$ using the following steps:

Factored the quadratic expression: We factored the quadratic expression $x^2 - 5x$ as $x(x - 5)$ .
Found the critical points: We found the critical points of the quadratic inequality, which are $x = 0$ and $x = 5$ .
Tested the intervals: We tested the intervals between the critical points to determine which intervals satisfy the inequality.
Determined the solution set: Based on the results of the interval testing, we determined the solution set of the quadratic inequality.

The solution set of the quadratic inequality is $(-\infty, 0] \cup [2, 5] \cup [5, \infty)$ .

Final Answer

$The final answer is $\boxed{(-\infty, 0] \cup [2, 5] \cup [5, \infty)}$.<br/> **Quadratic Inequality Q&A: Frequently Asked Questions**$

Introduction

In our previous article, we solved the quadratic inequality $x(x-5) \leq 14$ using the following steps:

Factored the quadratic expression: We factored the quadratic expression $x^2 - 5x$ as $x(x - 5)$ .
Found the critical points: We found the critical points of the quadratic inequality, which are $x = 0$ and $x = 5$ .
Tested the intervals: We tested the intervals between the critical points to determine which intervals satisfy the inequality.
Determined the solution set: Based on the results of the interval testing, we determined the solution set of the quadratic inequality.

In this article, we will answer some frequently asked questions about quadratic inequalities.

Q: What is a quadratic inequality?

A quadratic inequality is a type of mathematical expression that involves a quadratic function and an inequality sign. It is a quadratic expression that is either greater than, less than, greater than or equal to, or less than or equal to a certain value.

Q: How do I solve a quadratic inequality?

To solve a quadratic inequality, you need to follow these steps:

Factored the quadratic expression: Factor the quadratic expression to obtain a product of two binomial expressions.
Found the critical points: Find the critical points of the quadratic inequality, which are the values of $x$ that make the quadratic expression equal to zero.
Tested the intervals: Test the intervals between the critical points to determine which intervals satisfy the inequality.
Determined the solution set: Based on the results of the interval testing, determine the solution set of the quadratic inequality.

Q: What are the critical points of a quadratic inequality?

The critical points of a quadratic inequality are the values of $x$ that make the quadratic expression equal to zero. These points divide the number line into intervals, and each interval may or may not satisfy the inequality.

Q: How do I test the intervals of a quadratic inequality?

To test the intervals of a quadratic inequality, you need to substitute a test value from each interval into the quadratic expression. If the result is less than or equal to the given value, then the interval satisfies the inequality.

Q: What is the solution set of a quadratic inequality?

The solution set of a quadratic inequality is the set of all values of $x$ that satisfy the inequality. It is the union of the intervals that satisfy the inequality.

Q: Can a quadratic inequality have multiple solution sets?

Yes, a quadratic inequality can have multiple solution sets. This occurs when the quadratic expression has multiple critical points, and each critical point divides the number line into multiple intervals.

Q: How do I graph a quadratic inequality?

To graph a quadratic inequality, you need to graph the quadratic function and shade the regions that satisfy the inequality. The regions that satisfy the inequality are the regions where the quadratic function is less than or equal to the given value.

Q: Can a quadratic inequality be solved using algebraic methods?

Yes, a quadratic inequality can be solved using algebraic methods. However, these methods may not always be the most efficient or effective way to solve the inequality.

Conclusion

In this article, we answered some frequently asked questions about quadratic inequalities. We hope that this article has provided you with a better understanding of quadratic inequalities and how to solve them.

Final Answer

The final answer is $\boxed{(-\infty, 0] \cup [2, 5] \cup [5, \infty)}$ .