Simplifying the Logarithmic Term

Oct 13, 2025 by wbrum.org 131 views

Introduction

In this article, we will delve into the world of logarithms and evaluate the given expression $\log _5(25) + \log _5(125)$ . Logarithms are a fundamental concept in mathematics, and understanding their properties is crucial for solving various mathematical problems. The expression we are dealing with involves the sum of two logarithmic terms with the same base, which can be simplified using the properties of logarithms.

Understanding Logarithms

Before we proceed with the evaluation of the given expression, let's briefly review the concept of logarithms. A logarithm is the inverse operation of exponentiation. In other words, it is the power to which a base number must be raised to obtain a given value. For example, $\log _5(25)$ represents the power to which 5 must be raised to obtain 25.

Properties of Logarithms

There are several properties of logarithms that we will use to simplify the given expression. These properties include:

Product Property: $\log _a(xy) = \log _a(x) + \log _a(y)$
Quotient Property: $\log _a(\frac{x}{y}) = \log _a(x) - \log _a(y)$
Power Property: $\log _a(x^n) = n\log _a(x)$

Evaluating the Expression

Now that we have reviewed the properties of logarithms, let's proceed with the evaluation of the given expression.

$\log _5(25) + \log _5(125)$

Using the product property, we can rewrite the expression as:

$\log _5(25 \times 125)$

Now, let's simplify the expression inside the logarithm:

$25 \times 125 = 3125$

So, the expression becomes:

$\log _5(3125)$

Simplifying the Logarithmic Term

Now that we have simplified the expression inside the logarithm, let's focus on the logarithmic term itself. We can rewrite the logarithmic term as:

$\log _5(3125) = \log _5(5^5)$

Using the power property, we can rewrite the logarithmic term as:

$5\log _5(5)$

Evaluating the Logarithmic Term

Now that we have simplified the logarithmic term, let's evaluate it. Using the definition of logarithms, we can rewrite the logarithmic term as:

$5\log _5(5) = 5 \times 1$

So, the final value of the logarithmic term is:

$5$

Conclusion

In this article, we evaluated the expression $\log _5(25) + \log _5(125)$ using the properties of logarithms. We simplified the expression inside the logarithm and then focused on the logarithmic term itself. Using the power property, we were able to rewrite the logarithmic term as $5\log _5(5)$ , which evaluates to 5. This demonstrates the importance of understanding the properties of logarithms in solving mathematical problems.

Frequently Asked Questions

What is the value of $\log _5(25)$ ? $\log _5(25) = 2$
What is the value of $\log _5(125)$ ? $\log _5(125) = 3$
What is the value of $\log _5(3125)$ ? $\log _5(3125) = 5$

Final Answer

The final answer to the expression $\log _5(25) + \log _5(125)$ is $\boxed{5}$ .

Introduction

In our previous article, we evaluated the expression $\log _5(25) + \log _5(125)$ using the properties of logarithms. Logarithms and exponents are fundamental concepts in mathematics, and understanding their properties is crucial for solving various mathematical problems. In this article, we will answer some frequently asked questions related to logarithms and exponents.

Q&A

Q1: What is the difference between a logarithm and an exponent?

A1: A logarithm is the inverse operation of exponentiation. In other words, it is the power to which a base number must be raised to obtain a given value. For example, $\log _5(25)$ represents the power to which 5 must be raised to obtain 25. On the other hand, an exponent is a number that is raised to a power. For example, $5^3$ represents 5 raised to the power of 3.

Q2: What is the value of $\log _5(5)$ ?

A2: Using the definition of logarithms, we can rewrite the logarithmic term as:

$\log _5(5) = 1$

This is because 5 raised to the power of 1 is equal to 5.

Q3: What is the value of $\log _5(1)$ ?

A3: Using the definition of logarithms, we can rewrite the logarithmic term as:

$\log _5(1) = 0$

This is because any number raised to the power of 0 is equal to 1.

Q4: What is the value of $\log _5(5^3)$ ?

A4: Using the power property, we can rewrite the logarithmic term as:

$3\log _5(5)$

Using the definition of logarithms, we can rewrite the logarithmic term as:

$3 \times 1 = 3$

So, the final value of the logarithmic term is:

$3$

Q5: What is the value of $\log _5(\frac{1}{5})$ ?

A5: Using the quotient property, we can rewrite the logarithmic term as:

$\log _5(1) - \log _5(5)$

Using the definition of logarithms, we can rewrite the logarithmic term as:

$0 - 1 = -1$

So, the final value of the logarithmic term is:

$-1$

Q6: What is the value of $\log _5(5^x)$ ?

A6: Using the power property, we can rewrite the logarithmic term as:

$x\log _5(5)$

Using the definition of logarithms, we can rewrite the logarithmic term as:

$x \times 1 = x$

So, the final value of the logarithmic term is:

$x$

Q7: What is the value of $\log _5(\frac{5^x}{5^y})$ ?

A7: Using the quotient property, we can rewrite the logarithmic term as:

$\log _5(5^x) - \log _5(5^y)$

Using the power property, we can rewrite the logarithmic term as:

$x\log _5(5) - y\log _5(5)$

Using the definition of logarithms, we can rewrite the logarithmic term as:

$x - y$

So, the final value of the logarithmic term is:

$x - y$

Conclusion

In this article, we answered some frequently asked questions related to logarithms and exponents. We covered topics such as the difference between a logarithm and an exponent, the value of logarithmic terms, and the properties of logarithms. We hope that this article has provided you with a better understanding of logarithms and exponents.

Frequently Asked Questions

What is the value of $\log _5(5^x)$ ? $\log _5(5^x) = x$
What is the value of $\log _5(\frac{5^x}{5^y})$ ? $\log _5(\frac{5^x}{5^y}) = x - y$
What is the value of $\log _5(1)$ ? $\log _5(1) = 0$
What is the value of $\log _5(5)$ ? $\log _5(5) = 1$

Final Answer

The final answer to the expression $\log _5(25) + \log _5(125)$ is $\boxed{5}$ .