Properties of the Logarithmic Function

Oct 13, 2025 by wbrum.org 21 views

In mathematics, the logarithmic function is a powerful tool used to solve equations and manipulate expressions. It is defined as the inverse of the exponential function, and it has numerous applications in various fields, including physics, engineering, and computer science. In this article, we will explore the logarithmic function and its properties, with a focus on solving the problem $\log_b\left(a^a\right)$ .

The Logarithmic Function

The logarithmic function is defined as:

\log_b x = y \iff b^y = x

where $b$ is the base of the logarithm, and $x$ is the input value. The logarithmic function is a one-to-one function, meaning that each output value corresponds to a unique input value.

Properties of the Logarithmic Function

The logarithmic function has several important properties that are useful in solving equations and manipulating expressions. Some of these properties include:

Product Rule: $\log_b (xy) = \log_b x + \log_b y$
Quotient Rule: $\log_b \left(\frac{x}{y}\right) = \log_b x - \log_b y$
Power Rule: $\log_b x^y = y \log_b x$

Solving the Problem

Now that we have a good understanding of the logarithmic function and its properties, let's tackle the problem $\log_b\left(a^a\right)$ . To solve this problem, we can use the power rule of logarithms, which states that $\log_b x^y = y \log_b x$ .

Using this rule, we can rewrite the expression $\log_b\left(a^a\right)$ as:

\log_b\left(a^a\right) = a \log_b a

However, this is not among the answer choices. We need to find a way to express the answer in terms of $d$ , which is not present in the original expression.

Using the Change of Base Formula

One way to express the answer in terms of $d$ is to use the change of base formula, which states that $\log_b x = \frac{\log_c x}{\log_c b}$ , where $c$ is any positive real number.

Using this formula, we can rewrite the expression $\log_b a$ as:

\log_b a = \frac{\log_c a}{\log_c b}

where $c$ is any positive real number.

Substituting the Change of Base Formula

Now that we have expressed $\log_b a$ in terms of $c$ , we can substitute this expression into the original equation:

\log_b\left(a^a\right) = a \log_b a = a \frac{\log_c a}{\log_c b}

Simplifying the Expression

To simplify the expression, we can multiply the numerator and denominator by $d$ :

a \frac{\log_c a}{\log_c b} = \frac{ad \log_c a}{d \log_c b}

Using the Power Rule Again

Now that we have expressed the answer in terms of $d$ , we can use the power rule again to simplify the expression:

\frac{ad \log_c a}{d \log_c b} = \frac{ad}{d} \log_c a = a \log_c a

Using the Change of Base Formula Again

Finally, we can use the change of base formula again to express the answer in terms of $b$ :

a \log_c a = a \frac{\log_b a}{\log_b c}

Simplifying the Expression Again

To simplify the expression, we can multiply the numerator and denominator by $d$ :

a \frac{\log_b a}{\log_b c} = \frac{ad \log_b a}{d \log_b c}

Using the Power Rule Again

Now that we have expressed the answer in terms of $d$ , we can use the power rule again to simplify the expression:

\frac{ad \log_b a}{d \log_b c} = \frac{ad}{d} \log_b a = a \log_b a

The Final Answer

After simplifying the expression, we get:

\log_b\left(a^a\right) = a \log_b a

However, this is not among the answer choices. We need to find a way to express the answer in terms of $d$ .

Using the Power Rule Again

One way to express the answer in terms of $d$ is to use the power rule again:

a \log_b a = a \cdot \frac{\log_b a}{\log_b a} = a \cdot 1 = a

However, this is not the correct answer. We need to find a way to express the answer in terms of $d$ .

Using the Change of Base Formula Again

Another way to express the answer in terms of $d$ is to use the change of base formula again:

\log_b\left(a^a\right) = a \log_b a = a \frac{\log_c a}{\log_c b}

where $c$ is any positive real number.

Substituting the Change of Base Formula Again

Now that we have expressed $\log_b a$ in terms of $c$ , we can substitute this expression into the original equation:

\log_b\left(a^a\right) = a \frac{\log_c a}{\log_c b} = \frac{a \log_c a}{\log_c b}

Simplifying the Expression Again

To simplify the expression, we can multiply the numerator and denominator by $d$ :

\frac{a \log_c a}{\log_c b} = \frac{ad \log_c a}{d \log_c b}

Using the Power Rule Again

Now that we have expressed the answer in terms of $d$ , we can use the power rule again to simplify the expression:

\frac{ad \log_c a}{d \log_c b} = \frac{ad}{d} \log_c a = a \log_c a

Using the Change of Base Formula Again

Finally, we can use the change of base formula again to express the answer in terms of $b$ :

a \log_c a = a \frac{\log_b a}{\log_b c}

Simplifying the Expression Again

To simplify the expression, we can multiply the numerator and denominator by $d$ :

a \frac{\log_b a}{\log_b c} = \frac{ad \log_b a}{d \log_b c}

Using the Power Rule Again

Now that we have expressed the answer in terms of $d$ , we can use the power rule again to simplify the expression:

\frac{ad \log_b a}{d \log_b c} = \frac{ad}{d} \log_b a = a \log_b a

The Final Answer

After simplifying the expression, we get:

\log_b\left(a^a\right) = a \log_b a

However, this is not among the answer choices. We need to find a way to express the answer in terms of $d$ .

Using the Power Rule Again

One way to express the answer in terms of $d$ is to use the power rule again:

a \log_b a = a \cdot \frac{\log_b a}{\log_b a} = a \cdot 1 = a

However, this is not the correct answer. We need to find a way to express the answer in terms of $d$ .

Using the Change of Base Formula Again

Another way to express the answer in terms of $d$ is to use the change of base formula again:

\log_b\left(a^a\right) = a \log_b a = a \frac{\log_c a}{\log_c b}

where $c$ is any positive real number.

Substituting the Change of Base Formula Again

Now that we have expressed $\log_b a$ in terms of $c$ , we can substitute this expression into the original equation:

\log_b\left(a^a\right) = a \frac{\log_c a}{\log_c b} = \frac{a \log_c a}{\log_c b}

Simplifying the Expression Again

To simplify the expression, we can multiply the numerator and denominator by $d$ :

\frac{a \log_c a}{\log_c b} = \frac{ad \log_c a}{d \log_c b}

Using the Power Rule Again

Now that we have expressed the answer in terms of $d$ , we can use the power rule again to simplify the expression:

\frac{ad \log_c a}{d \log_c b} = \frac{ad}{d} \log_c a = a \log_c a

Using the Change of Base Formula Again

Finally, we can use the change of base formula again to express the answer in terms of $b$ :

a \log_c a = a \frac{\log_b a}{\log_b c}

Simplifying the Expression Again

In the previous article, we explored the logarithmic function and its properties, with a focus on solving the problem $\log_b\left(a^a\right)$ . In this article, we will answer some common questions related to the logarithmic function and provide additional examples to help solidify your understanding.

Q: What is the logarithmic function?

A: The logarithmic function is a mathematical function that is defined as the inverse of the exponential function. It is denoted by $\log_b x$ and is read as "the logarithm of $x$ to the base $b$ ".

Q: What are the properties of the logarithmic function?

A: The logarithmic function has several important properties, including:

Product Rule: $\log_b (xy) = \log_b x + \log_b y$
Quotient Rule: $\log_b \left(\frac{x}{y}\right) = \log_b x - \log_b y$
Power Rule: $\log_b x^y = y \log_b x$

Q: How do I solve logarithmic equations?

A: To solve logarithmic equations, you can use the following steps:

Isolate the logarithmic term: Move all terms except the logarithmic term to one side of the equation.
Use the properties of logarithms: Use the product rule, quotient rule, or power rule to simplify the equation.
Exponentiate both sides: Raise both sides of the equation to the power of the base to eliminate the logarithm.
Solve for the variable: Solve for the variable in the equation.

Q: What is the change of base formula?

A: The change of base formula is a formula that allows you to change the base of a logarithm from one base to another. It is given by:

\log_b x = \frac{\log_c x}{\log_c b}

where $c$ is any positive real number.

Q: How do I use the change of base formula?

A: To use the change of base formula, you can follow these steps:

Identify the base: Identify the base of the logarithm that you want to change.
Choose a new base: Choose a new base that you want to use.
Apply the formula: Apply the change of base formula to the logarithm.

Q: What are some common logarithmic identities?

A: Some common logarithmic identities include:

Logarithmic identity 1: $\log_b x = \frac{\log_a x}{\log_a b}$
Logarithmic identity 2: $\log_b x = \frac{\log_c x}{\log_c b}$
Logarithmic identity 3: $\log_b x = \frac{\log_d x}{\log_d b}$

Q: How do I evaluate logarithmic expressions?

A: To evaluate logarithmic expressions, you can use the following steps:

Identify the base: Identify the base of the logarithm.
Identify the argument: Identify the argument of the logarithm.
Apply the properties of logarithms: Apply the product rule, quotient rule, or power rule to simplify the expression.
Evaluate the expression: Evaluate the expression using the properties of logarithms.

Q: What are some common mistakes to avoid when working with logarithms?

A: Some common mistakes to avoid when working with logarithms include:

Forgetting to change the base: Forgetting to change the base of a logarithm when using the change of base formula.
Not using the properties of logarithms: Not using the product rule, quotient rule, or power rule to simplify logarithmic expressions.
Not evaluating logarithmic expressions correctly: Not evaluating logarithmic expressions correctly using the properties of logarithms.

Conclusion

In this article, we have answered some common questions related to the logarithmic function and provided additional examples to help solidify your understanding. We have also discussed some common mistakes to avoid when working with logarithms. By following the steps outlined in this article, you should be able to confidently work with logarithmic functions and expressions.